Thursday, July 24, 2025

Rotation, reflection, orientation

Is this true:
“Suppose that a line is chosen from within a plane, and the plane is rotated 180° clockwise around this line. This will mirror the plane, reflecting its points such that the points leftward from the line become rightward from it and vice-versa. But suppose that the rotation is done counter-clockwise instead. Then the same thing happens, and there is no difference.”

Yes – it’s absolutely true. Here’s why:

  1. A 180° rotation about a line in the plane acts like a mirror reflection across that line.

    • Take for example the horizontal $x$–axis in the $xy$–plane. If you rotate the plane 180° about that axis (in three‑dimensional space), any point $(x,y,0)$ goes to $(x,-y,0)$. That is exactly the effect of reflecting across the $x$–axis.
    • More generally, for any line $L\subset P$, the restriction to $P$ of the half‐turn about $L$ is the involution “reflect across $L$.”
  2. “Clockwise” versus “counter‑clockwise” makes no difference at 180°.

    • Angles are taken modulo 360°, so rotating by $+180°$ or by $-180°$ lands you in the same place:

    $$ R_{L}(+180°)\;=\;R_{L}(-180°). $$

    • In other words, a half‑turn is its own inverse, and the sign convention for direction drops out.
  3. Orientation flip on the plane.

    • In three dimensions the rotation by 180° about a line lying in a plane reverses the plane’s “sidedness” (it sends a chosen normal vector to its negative). That’s exactly what a reflection in the line does: it reverses orientation in the plane.

So rotating $P$ by 180° around $L$ is the same map as reflecting $P$ across $L$, and whether you spin “clockwise” or “counter‑clockwise” your half‑turn is identical.

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