powers of groups of prime order are vector spaces
Yes, that's correct — groups of prime order have an important connection to vector spaces, under the right interpretation.
Key Idea:
If $G$ is a group of prime order $p$, then:
- $G$ is a cyclic group (since all groups of prime order are cyclic),
- Every element $g \in G$ satisfies $g^p = e$, the identity element,
- If $G$ is also abelian and we consider it as a module over $\mathbb{F}_p$, then it becomes a vector space over $\mathbb{F}_p$.
Explanation:
Let’s formalize it:
1. Group of Prime Order:
Let $G$ be a group with order $p$, a prime number.
- Then $G$ is cyclic: $G \cong \mathbb{Z}/p\mathbb{Z}$,
- It is abelian, because all cyclic groups are abelian.
2. Powers and Vector Space Structure:
If you now look at a finite abelian group $G$ where every element has order dividing a prime $p$, i.e., for all $g \in G$, $g^p = e$, then:
- $G$ is a $\mathbb{F}_p$-vector space.
Why?
Because we can define scalar multiplication by elements of $\mathbb{F}_p$ as:
$$ a \cdot g = g^a $$
This satisfies the vector space axioms because exponentiation respects the group operation.
Thus:
Any abelian group $G$ where every element has order $p$ (a prime) can be regarded as a vector space over $\mathbb{F}_p$.
This includes:
- Any group of order $p$,
- More generally, any abelian $p$-group of exponent $p$.
Examples:
- $\mathbb{Z}/p\mathbb{Z} \cong \mathbb{F}_p$: 1-dimensional vector space over $\mathbb{F}_p$,
- $(\mathbb{Z}/p\mathbb{Z})^n \cong \mathbb{F}_p^n$: n-dimensional vector space over $\mathbb{F}_p$.
Conclusion:
So yes — the powers (i.e., elements raised to integers) in abelian groups of prime order, or more generally abelian $p$-groups of exponent $p$, behave like elements of a vector space over the finite field $\mathbb{F}_p$.
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